A student recently asked us how to solve the following problem using the halflife equation: "Cobalt60 has a halflife of 5.2 years. Starting with 32 grams of cobalt60, how much of the original isotope will remain after 26 years?"
The halflife equation is N = N0(1/2)^(t/h) where N is the amount remaining, N0 is the original amount, t is the amount of time that has passed, and h is the halflife. Thus we obtain:
N = (32 g)(1/2)^(26 y/5.2 y)
N = (32 g)(1/2)^5
N = (32 g)(0.03125)
N = 1 g
Diagnostic CP Q38

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Diagnostic CP Q38
Sophia Stone
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