A student recently asked us how to solve the following problem using the halflife equation: "Cobalt60 has a halflife of 5.2 years. Starting with 32 grams of cobalt60, how much of the original isotope will remain after 26 years?"
The halflife equation is N = N0(1/2)^(t/h) where N is the amount remaining, N0 is the original amount, t is the amount of time that has passed, and h is the halflife. Thus we obtain:
N = (32 g)(1/2)^(26 y/5.2 y)
N = (32 g)(1/2)^5
N = (32 g)(0.03125)
N = 1 g
Diagnostic CP Q38

 Posts: 30
 Joined: Tue Aug 01, 2017 11:49 am
Diagnostic CP Q38
Sophia Stone
PCAT Content Manager
Next Step Test Prep
PCAT Content Manager
Next Step Test Prep