### AAMC Physics Qbank#65

Posted:

**Wed Aug 07, 2019 4:05 pm**(3.0 × 10^8 m/s)/( 10^15 Hz) = 3.0 × 10–7 m

How do the seconds cancel out here? I know Hz is 1/s. So its (m/s)/(1/s).

When working this problem I originally multiplied (3.0 × 10^8 m/s) by ( 10^15 Hz) to get 3x10^23

How do the seconds cancel out here? I know Hz is 1/s. So its (m/s)/(1/s).

When working this problem I originally multiplied (3.0 × 10^8 m/s) by ( 10^15 Hz) to get 3x10^23