(3.0 × 10^8 m/s)/( 10^15 Hz) = 3.0 × 10–7 m
How do the seconds cancel out here? I know Hz is 1/s. So its (m/s)/(1/s).
When working this problem I originally multiplied (3.0 × 10^8 m/s) by ( 10^15 Hz) to get 3x10^23
AAMC Physics Qbank#65

 Posts: 616
 Joined: Sat Mar 30, 2019 8:39 pm
Re: AAMC Physics Qbank#65
Right, you wanted to divide those two quantities because lambda = c/f
Dividing by 1/s is the same as multiplying by s. Or for the entire term, dividing by 10^15 1/s is the same as multiplying by 10^15 s.
I've attached a quick image that might help a little. But essentially you are on the right track, just don't forgot to flip the whole term when multiplying by a reciprocal, not just the units.
Dividing by 1/s is the same as multiplying by s. Or for the entire term, dividing by 10^15 1/s is the same as multiplying by 10^15 s.
I've attached a quick image that might help a little. But essentially you are on the right track, just don't forgot to flip the whole term when multiplying by a reciprocal, not just the units.
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