CR Electrochemical Cells Quiz 1 Q1

alexpie
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Joined: Sat May 06, 2017 7:27 pm

CR Electrochemical Cells Quiz 1 Q1

Postby alexpie » Mon May 29, 2017 9:57 pm

http://imgur.com/a/eGpLf

Above is the picture to to reaction I am talking about if you wanna save time. I am just wondering, how do we know that the N oxidation state is +5? Is it because each oxygen is -2 (overall -6) and the N has a lone pair of electrons so that would bring the oxidation state down to +5? Or does this include anything with the Cu or Ag at all?
NS_Tutor_Andrew
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Re: CR Electrochemical Cells Quiz 1 Q1

Postby NS_Tutor_Andrew » Tue May 30, 2017 12:05 pm

Hi alexpie,

This does indeed have to do with the Cu/Ag. You can see it most clearly with Ag(NO3): you get -6 from O3, +1 from Ag, and N must be +5 to balance it out. Cu(NO3)2 is a little trickier but the math will still work out, with Cu having an oxidation state of +2: -12 from 2*O3, +2 from Cu, leaving a total of +10 that must be split between 2 N atoms, each of which have an oxidation state of +5.

Hope this helps!
Andrew D.
Content Manager, Next Step Test Prep.
alexpie
Posts: 17
Joined: Sat May 06, 2017 7:27 pm

Re: CR Electrochemical Cells Quiz 1 Q1

Postby alexpie » Thu Jun 01, 2017 1:16 pm

Thank you!!! This helps a lot

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