Chemistry Question from the textbook

SungHoonPark97
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Chemistry Question from the textbook

Postby SungHoonPark97 » Tue May 22, 2018 12:41 pm

Question 5 of Ch.1 end of chapter practice passage.

I do not understand why you divide 1.85 (the molecular dipole of water) by 2 for the adjacent side of the 55 degree angle. I thought since the molecular dipole is perpendicular to the H-O-H angle, the adjacent side should remain 1.85.
NS_Tutor_Katelyn
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Re: Chemistry Question from the textbook

Postby NS_Tutor_Katelyn » Thu Jun 07, 2018 2:37 pm

SungHoonPark97 wrote:Question 5 of Ch.1 end of chapter practice passage.

I do not understand why you divide 1.85 (the molecular dipole of water) by 2 for the adjacent side of the 55 degree angle. I thought since the molecular dipole is perpendicular to the H-O-H angle, the adjacent side should remain 1.85.


It needs to be divided by two because the molecular dipole is contributed to by two OH bonds. Each OH bonds creates 0.925 of the 1.85 dipole.
Katelyn Sawyer
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