Bichem Chp 6 Independent Q 1

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Joined: Thu Aug 16, 2018 6:35 pm

Bichem Chp 6 Independent Q 1

Postby mit » Thu Aug 16, 2018 7:01 pm

Hi again,
Isn't option C also true?
That fructofuranose is a pentose, and fructopyranose is a hexose...

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Joined: Fri May 25, 2018 9:15 am

Re: Bichem Chp 6 Independent Q 1

Postby NS_Tutor_Will » Fri Aug 17, 2018 10:22 am

Hi Mit --

Remember, fructose is a hexose, so it will always have six carbons. The difference between the two compounds you mentioned is the size of the ring that they form. Fructopyranose forms a six-membered ring (with one -CH2OH group), while fructofuranose forms a five-membered ring (with two -CH2OH groups.

Hope that helps and good luck!

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